X^2+x-0.64=0

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Solution for X^2+x-0.64=0 equation: 



X^2+X-0.64=0

a = 1; b = 1; c = -0.64;
Δ = b2-4ac
Δ = 12-4·1·(-0.64)
Δ = 3.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{3.56}}{2*1}=\frac{-1-\sqrt{3.56}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{3.56}}{2*1}=\frac{-1+\sqrt{3.56}}{2}
$

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